Talk:EGR 224/Spring 2009

Homework 1

1.14

• You should assume Passive Sign Convention. DukeEgr93 16:21, 11 January 2009 (EST)

1.20

• This question regards current controlled voltage sources. How do you find the voltage across one? Consider problem 1.20 in A&S. The source is labeled 5I₀ with a current of 3 A passing through it. I thought the voltage is just 5*3=15 V, but using Kirchhoff's Voltage Law the voltage definitely should be 10 V. How do you utilize "5I₀" to find the voltage? Thanks! Brs16 12:24, 10 January 2009 (EST)
  • For the circuit in 1.20, the current controlled voltage source (CCVS) has an element equation that says the voltage drop is equal to \(5 I_0\) - the key here is to notice that \(I_0\) is the current through the 28 V element at the top of the circuit; it is listed as being 2 A. Given that, the CCVS has a voltage drop of 10 V, which can be verified with KVL. DukeEgr93 12:10, 11 January 2009 (EST)